Question

how do you get the volume of NaOH for each trial and the molarity for each trial show work please thank you so much!!

also the average molarity

show detailed work thank you so much!!

File Edit View Insert Format Tools Table Window Help AutoSaver 5 27-Titration-Report Weekl-2 insert Draw Design Layout References Mailings Review View >> Share - BA Table Pictures Shapes Icons Add-ins Media Links Comment Header & Text Footer cach Ope necessary to obtain the results in the above table. These should include the equations used, substituted values, appropriate units, and results I. Standardization of NaOH Solution (Quantitative Trials: Data and Calculations) Trial 1 Trial 2 Trial 3 Mass of KHCH.O. 0.232g 0.296g 0.320g Moles of KHC HOA 0.00114 mol 0.00145 mol 0.00157 mol Moles of NaOH 0.00114 mol 0.00145 mol 0.00157 mol Buret Reading (final) 11.20 ml. 24.70 ml 39.20 ml Buret Reading (initial) 0.00 mL 11.20 ml. 24.70 ml Volume of NaOH used Molarity of NaOH Average NaOH Molarity 371 words English (United States) Focus quantitative trials and find an average molarity

Answer 1

Let us clear the doubts one by one below-

As you are titrating
KHC HO,
in the flask with
ΝαΟΗ
in the burette, the volume of
ΝαΟΗ
would be the -

Buret reading (Final)- Buret reading (Initial) = in mL.

VNaOH

The Molarity of NaOH is calculated using the definition of molarity which is-

No. of moles of NaOH/ Volume of NaOH in L = Molarity of NaOH.

nNaOH/VNaOH, (L) =

calculation i Molavrity of Nach: Tonial : n Nooit V nach (in 0.00114 mol o.0112 L [11.2mL=0.01121) (Mwaon) = 0.102(M) Naolt Trial 2: 0.00145 mol Nach 0.0135 L NO OH T13:5 mL 20.01357 = 0.107

m° CA Trial 3 : (Ms.)= O0 151mol Noo | ") 0.0145 L Naolt = 0.108(M) .: Aceroge molavity of Nautta 0.102(M) + 0.107cm) + 0.1 08 (m) 23 - 0.1056 (M) at 0.106(M).

File Edit View Insert Format Tools Table Window Help AutoSaver 5 27-Titration-Report Weekl-2 insert Draw Design Layout References Mailings Review View >> Share - BA Table Pictures Shapes Icons Add-ins Media Links Comment Header & Text Footer cach Ope necessary to obtain the results in the above table. These should include the equations used, substituted values, appropriate units, and results I. Standardization of NaOH Solution (Quantitative Trials: Data and Calculations) Trial 1 Trial 2 Trial 3 Mass of KHCH.O. 0.232g 0.296g 0.320g Moles of KHC HOA 0.00114 mol 0.00145 mol 0.00157 mol Moles of NaOH 0.00114 mol 0.00145 mol 0.00157 mol Buret Reading (final) 11.20 ml. 24.70 ml 39.20 ml Buret Reading (initial) 0.00 mL 11.20 ml 24.70 ml. Volume of NaOH used (11.20-0) 11.20mL (24.70-11.20) = 13.5 (39.20-24.70) = 14.50 mL Molarity of NaOH 0.102(M) 0.107 (M) 0.108(M) Average NaOH Molarity 0.106 M 371 words English (United States) Focus quantitative trials and find an average molarity