Question

To avoid oxygen toxicity and nitrogen narcosis, deep-sea divers breathe a specialized mixture of gas. Describe the mixture. a
Determine the mass of water formed when 125 L NH 3 (at 298 K and 1.50 atm) is reacted with 18.9 L of O2 (at 323 K and 1.1 atm
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Answer #1

1.ANSWER:

To avoid oxygen toxicity and nitrogen narcosis, deep-sea divers breathe a specialized mixture of gas that is Heliox which is a mixture of helium and oxygen. Mainly nitrox is used by a diver but it is not useful in deep-sea.

Hence, the fourth option is correct.

2.ANSWER:

Here,

Number of moles of NH3 = (PV)/(RT)

= (1.5 atm x 12.5 L)/(0.082057 L atm mol-1K-1 x 298 K)

= 0.767 moles

Number of moles of O2 = (PV)/(RT)

= (1.1 atm x 18.9 L)/(0.082057 L atm mol-1K-1 x 323 K)

= 0.784 moles

In reaction we can see that 4 moles of NH3 gives 6 moles of water

So, 1 moles of NH3 gives = 1.5 moles of water

and, 0.767 moles of NH3 gives = (1.5 x 0.767) moles of water

= 1.1505 moles of water.

Now,

The mass of water = number of moles x molar mass

= 1.1505 mol x 18.01528 g/mol

= 20.7 g H2O

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