Question

In the diagram below, nitrogen molecules are represented by unshaded spheres, oxygen molecules by gray spheres, and chlorine molecules by black spheres. If the total pressure in the container is 900. mm Hg, what is the partial pressure of chlorine? 2. What is the partial pressure of helium in a gas mixture of He, Xe and Ar if total pressure is 5.35 atm, temperature is 55 °C, mole fraction of xenon is 0.298, and mole fraction of argon is 0.433? 3. A glass vessel contains 28 g nitrogen gas. Assuming ideal behavior, which of the following processes below would double the pressure exerted on the walls of the vessel? a) adding enough mercury at room temperature to fill one- half the container b) raising the temperature of the container from 30 °C to 60 "C. c) raising the temperature of the container from -73 °C to 127 d) adding 28 g nitrogen gas 4. A 12.5 L scuba diving tank contains a helium-oxygen mixture made up of 24.2 g He and 4.32 g Oxygen at 298 K. Calculate the mole fraction and partial pressure of each component in the mixture and the total pressure of the mixture. 5. A mixture of chromium and zinc weighing 0.362 g was reacted with an excess of HCl. After all the metals in the mixture are reacted, 0.225 L of hydrogen gas was collected at 300.0K and 0.987 atm. Determine the mass percent of Zinc in the metal sample. Zinc reacts with HCl to produce zinc chloride and H, gas. Chromium reacts with HCl to produce chromium (III) chloride and H, gas. 6. Pressurized carbon dioxide inflators can be used to inflate a bicycle tire that has gone flat. These inflators use metal cartridges that contain 16.9 g Co,. At 298K, to what pressure (in psi) on the pressure gauge can the carbon dioxide in the cartridge inflate a 3.45 L mountain bike tire? (Note: the gauge pressure is the difference between the total pressure and the atmospheric pressure, which for this problem is 14.7 psi/1 atm).

Answer 1

Partial Pressure - PTotal Rd xa - mole fraction - Protal = goo mm Hg Pe = 900 x 10 nehnat No tw) = 450 mm Hg Note - one sphese is taken as one mole of particular molecule. 2. Protal = 5.35 atm xxe = 0.298 XA = 0.433 He = 1-(0.298 +0.433) = 0.269 PHe = Protal Rue 5.35 x 0.269 = 1.44 atm (6) is according correct option to Gay-Lussac Law P&T 11 - 12 94.2 4. mole fraction of He = (a ne 6.05 - 0.96 6.32 6.05 6.05+0.27 0.96 = 0.04 Xo₂ = 1-

Partial pressure of the - HRT - 6.05 x 0.0821 x 298 = 11.8 atm Partial pressure of O2 = nRT - 0.27% 0-08213 12.5 12 .5 = 0.55 atm 0.0821 L atm (k mol R = Protal = = - Pre + Poz 11.8 +0.53 12.33 atm