A2.09-L sample of gas at (574.6°C. 0.447 atm) is cooled to 310.6°C. Assuming constant pressure, calculate...

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Question

science chemistry

Answer 1

Answer #1

ANSWER:

Given,

Volume, V1 = 2.09 L

Temperature, T1 = 574.6 oC = 847.75 K

Pressure, P = 0.447 atm

Temperature, T2 = 310.6 oC = 583.75 K

We know that,

PV = nRT

Here P, n & R is constant. So,

For two condition :

V 2.09L 847.75K 538.75K)

So, V2 = 1.33 L or 13.3E-1 L

Hence, final volume of gas is 13.3E-1 Litres.

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Answer 2

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