Homework Answers
Mass of NaCN used = 0.93 g
Molar mass of NaCN = 49.01 g/mol
Moles of NaCN = 0.93 g / 49.01 g/mol = 0.0189 Moles
one mole of NaCN (or any molecule) will be having Avogadro's number (6.032 x 1023) of molecules.
No of NaCN molecules in 0.93 g = 0.0189 x 6.032 x 1023 = 1.14 x 1022 Molecules
0.93 g of NaCN has of 1.14 x 1022 Molecules
Hence option B is correct answer
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