A force of 50 N is applied tangentially to the rim of a solid disk of...
A force of 50 N is applied tangentially to the rim of a solid disk of radius 0.18 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 115 rad/s2. Determine the mass of the disk.
Homework Answers
By torque equation,
torque = i alpha
50*0.18 = (0.5 mr^2)* alpha
9 = 0.5*(m*0.18^2)*115
m = 9/[0.5*0.18^2*115]
= 4.831 kg answer
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