Question

175.0 grams of an unknown metal at 85.0°C is added to 75.00 grams of water (cs = 4.184 J/g.°C) at 21.0°C in an insulated container. If the final temperature of the metal and water is 26.2°C then what is the specific heat capacity (Cs) of the metal? Select one: a. -0.16 J/g.°C b. 0.16 J/g.°C c. 6.3 J/g.°C O d.-6.3 J/g.°C e. 1.4 J/g.°C

Answer 1

he temperature of 75 gm water is increased from 2000 to 26:2e and temperature of 1759m metal is decreased from 85e to 26.2€ . this y due to heat transfer from hot metal to cold water. As the container insulated the heat given by metal is equal to heat taken by water. Amount of heat transforqed is given by, g- heat transferred g= m. egiat m= mass of the substance cs = specific heat of substance At a temperature change = final -initial temp For metal, 3M = 1759 x CsX (26.2-85) = - 10290 Cs gole -re signifies heat is released. For water, J/g. ve X (2612-21) & Sw = 75 gx 4.184 = 1631.76 ] . SM z ow 1029065 = 16311761 10290 vlige Cs = 1631-76 J/g.ee = 0.158 ilge ~ 0.16 II gre (option b) Specific heat can not be negative. in specific heat capacity of metal = 0.167/gre. (option b) VI