When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 14.0°C, the temperature of the water rises to 17.5°C. Assume that no heat is lost to the surroundings. What is the specific heat of the metal? The specific heat of water is 4.184 J/g·°C.
When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 14.0°C,...
1. (10 pts) A 150.0 g sample of a metal at 75.0 °C is added to 150.0 g H20 at 15.0 °C (s.h. = 4.184 J/g °C). The temperature of the water rises to 18.3 °C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water.
175.0 grams of an unknown metal at 85.0°C is added to 75.00 grams of water (cs = 4.184 J/g.°C) at 21.0°C in an insulated container. If the final temperature of the metal and water is 26.2°C then what is the specific heat capacity (Cs) of the metal? Select one: a. -0.16 J/g.°C b. 0.16 J/g.°C c. 6.3 J/g.°C O d.-6.3 J/g.°C e. 1.4 J/g.°C
72.0 grams of an unknown metal at 95.0oC is added to 115.0 grams of water (cs = 4.184 J/g•oC) at 21.0oC in an insulated container. If the final temperature of the metal and water is 27.3oC then what is the specific heat capacity (cs) of the metal?
44.0 grams of an unknown metal at 99.0oC is added to 80.0 grams of water (cs = 4.184 J/g•oC) at 24.0oC in an insulated container. If the final temperature of the metal and water is 28.4oC then what is the specific heat capacity (cs) of the metal?
A chunk of mercury at 80.8°C was added to 200.0 g of water at 15.5°C. The specific heat of mercury is 0.14 J/gºC, and the specific heat of water is 4.184 J/gºC. When the temperature stabilized, the temperature of the mixture was 20.9°C. Assuming no heat was lost to the surroundings, what was the mass of mercury added? a) 399 g b) 4948 539 g d) 2.08 kg e) 682 g
How many grams of ice at -15°C must be added to 705 grams of water that is initially at a temperature of 88°C to produce water at a final temperature of 11°C. Assume that no heat is lost to the surroundings and that the container has negligible mass. The specific heat of liquid water is 4190 J/kg·C° and of ice is 2050 J/kg·C°. For water the normal melting point is 0.00°C and the heat of fusion is 334 × 103...
Practice With Calorimetry And Heat 1. 75.0 g of cast iron was heated to 100°C and then plunged into 100 g of water at 23.0°C. Calculate the final temperature. Cast iron has specific heat of 0.46 J/gºc 2. A 25.0 g sample of an unknown metal at 99.5°C is placed into a calorimeter holding 50.0 g of water at 22.3°C. The final temperature was 26.2°C; what was the specific heat of the metal? 3. 30.0 g of water at 7.00°C...
Consider the dissolution of 1.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreased by 0.93 oC. The heat capacity of the calorimeter is 42.2 J/oC. The density of the water (and the solution) is 1.00 g/mL. The specific heat capacity of the solution is 4.184 J/goC. Identify the surroundings. Group of answer choices Salt dissolving in the water Calorimeter Water Solution and calorimeter
A 25.00 gram sample of an unknown metal initially at 99.0 degrees Celsius is added to 50.00 grams of water initially at 12.16 degrees Celsius. The final temperature of the metal and water is 20.15 degrees Celsius. Calculate the specific heat of the metal. (The specific heat of water is 4.184 J/g*C). (HINTS: Recall that the q of a system is equal to the -q of the surroundings. So you can set up two equations here: one for the loss...
A calorimeter contains 27.0 mL of water at 14.0 ∘C . When 2.00 g of X (a substance with a molar mass of 77.0 g/mol ) is added, it dissolves via the reaction X(s)+H2O(l)→X(aq) and the temperature of the solution increases to 26.5 ∘C . Calculate the enthalpy change, ΔH, for this reaction per mole of X. Assume that the specific heat of the resulting solution is equal to that of water [4.18 J/(g⋅∘C)], that density of water is 1.00...