Question

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15. Which of the following mixtures would result in a buffered solution? a. Mixing 100.0 mL of 0.100 M HCl with 100.0 mL of 0.100 M NaOH. b. Mixing 100.0 mL of 0.100 M NH3 (K5=1.8 x 10-5) with 100.0 mL of 0.100 M NaOH. c. Mixing 100.0 mL of 0.100 M HCl with 100.0 mL of 0.100 M NH; (K =18x 10 %. d. Mixing 50.0 mL of 0.100 M HCl with 100.0 mL of 0.100 M NH; (Kb - 1.8 x 10 %. ANS: Why did you choose your answer? 16. The solubility of Ca(OH)2 in water is 1.69 x 10 mol/L. The Ky value for Ca(OH)2 is a. 1.93 x 10-14 b. 4.83 x 10-15 c. 5.71 x 10-20 d. 1.69 x 104 c. none of these ANS: 17. Which of the following solid salts is more soluble in LOMH than in pure water? a. Naci b. CaCO3 c. Kai d. AgCI e. KNO3 ANS: 18. The best explanation for the dissolution of Zns in dilute HCI is that a. The zinc ion is amphoteric b. The sulfide-ion concentration is decreased by the fomation of He c. the sulfide-ion concentration is decreased by oxidation to self d. the zinc-ion concentration is decreased by the formation of a coloro complex e. The solubility product of ZnCl2 is less than that of Za ANS:

Answer 1

Bridic weak acid & its salt with Bas Audic buffer weak acid t its strong base sasic buffer', weak base+ salt with strong ace a strong acid & strong base - not buffer 2 weak base + strong base - not suffer & Strong acid & weak base - since amount /moles is equal so result in acidic solution. Weak base solution should be basic buffes not buffer - y since amount of acid is less a more NH3. So kuffer solution) consect option id] 16 CLCOH. det + 2014 DS - Ksp = [6d2+ ] 20132 = Sxlasta - 4s3 S = 1.69810 Smol/L) Ksp = 4X(1069 810 Ksp = 19.30781015 = 11.93 410-14 Ja option ( Nace+HgO - Nat+on+tt te - (NAOH + HCl) No effect of tt by CaCO3 + H2O Ca +2017+ HCO3A weak acid Since it will combine with OFT so equilibrium will shift in forward direction. Hence colubility will increase in acidic medium correct option to - 6 correct option se]