Question

all please, no mid way answers because then i dont get the help necessary.

Name 2) Nitrogen dioxide gas reacts with water to form nitric acid and nitrogen monoxide gas a) Write a balanced chemical equation for the reaction. b) If 5.Og nitrogen dioxide completed reacted, how many grams of nitric acid would form? c) If 5.0g water completed reacted, how many grams of nitric acid would form? d) What is the limited reagent? nitrogen dioxide, NO2 e) If 5.0g NO2 and 5.0g H20 are mixed, how much NO will form?

Answer 1

a) The balanced chemical reaction of NO2 with H2O is as follows:-

3 NO2 (g) + H2O (l) --> 2 HNO3 (aq) + NO (g)

b) To solve this question, we need to find moles of NO2 then use the ,ole to mole ratio to find moles of HNO3 and then multiply to it by molar mass of HNO3.

We will do this in one step by using dimensional analysis which is given by

5.0 g NO2 * (1 mol NO2/46.00 g NO2) * (2 mol HNO3/3 mol NO2) * (63.01 g HNO3/1 mol HNO3)

= 630.1 g HNO3/138

= 4.5659 = 4.6 g HNO3

c) Similarly to find grams of HNO3 by using grams of water, we use the same method as we do in b part.

5.0 g H2O * (1 mol H2O/18.02 g H2O) * (2 mol HNO3/1 mol H2O) * (63.01 g HNO3/ 1 mol HNO3)

= 630.1 g HNO3/18.02 = 34.9667 g HNO3 = 35 g HNO3

d) From above calculation, NO2 forms less gram of product. Therefore, limiting reactant for given reaction is NO2.

In more than four subpart, we solve only first four subparts. Thanks. If you have any doubts please mention in the comment box.