Question

How many moles of the reactant in excess are present after the reaction is completed?

Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation 3NO_2(g) + H_2O(l)right arrow2HN0_3(l) + NO(g) Suppose that 4 8 mol NO_2 and 1.1 mol H_2O combine and react completely Which reactant is in excess? How many moles of the reactant in excess are present after the reaction has completed?

Answer 1

A) Equation:3NO_2 + H_2O rightarrow 2NHO_3 + NO No of moles of NO produced from NO_2 = 4.8 mol NO_2 times 1 mol NO/1 mol NO_2 = 1.6 mol NO No of moles of NO produced from H_2O = 1.1 mol H_2O times 1 mol NO/1 mol H_2O = 1.1 mol NO since H_2O limits the production of NO, H_2O acts as the limiting reactant and NO_2 is the reactant present in excess B) Amount of H_2O initially present = 1.1 mol Amount of NO_2 initially present = 4.8 mol Amount of NO_2 reacted = 1.1 mol H_2O times 3 mol NO_2/1 mol H_2O