Question

When 14.2 g of NaNa and 12.0 g of Cl2Cl2 react, what is the mass, in grams, of NaClNaCl that is produced?

2Na(s)+Cl2(g)→2NaCl(s)

Answer 1

Molar mass of Na = 22.99 g/mol Molar mass of Cl2 = 70.91 g/mol Molar mass of NaCl = 58.44 g/mol Balanced chemical equation: 2 Na + 1 C12 → 2 Naci Theoretical moles ratio of Na : C12 = 2 : 1 Calculating number of moles: Mass of Na = 14.2 g Moles = Mass / Molar mass Moles of Na = [ 14.2 l 22.99 ) Moles of Na = 0.618 mol Mass of Cl2 = 12.0 g Moles = Mass / Molar mass Moles of Cl2 = ( 12.0 / 70.91 ) Moles of Cl2 = 0.169 mol Experimental moles ratio of Na : C12 = 0.618 : 0.169 3.650 : 1.000 Limiting reactant is C12 Excess reactant is Na Mass of products depends upon limiting reactant From balanced equation: 1 moles of Cl2 produces 2 moles of NaCl 0.169 moles of C12 produces ? moles of NaCl moles of NaCl = ( 2 / 1 ) * 0.169 moles of NaCl = 0.338 mol Calculating mass: Mass = Moles x Molar mass mass of NaCl = 0.338 x 58.44 mass of NaCl = 19.779 g mass of NaCl = 19.8 g