An electrochemical cell is based on these two half-reactions: Ox: Pb (8) Pb²+ (aq, 0.21 mol...

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Answer 1

Answer #1

Overall Balanced reaction :

3 Pb (s) + 2 MnO4-(aq) + 8H+ (aq) ------> 3 Pb2+(aq) + 2 MnO2 (s) + 4H2O (l)

E0cell = E0cathode - E0anode = + 1.81 V

Ecell = E0cell - (0.0592 V /6) log { [Pb2+]3 [MnO2 ]2 [H2O]4 / [Pb]3 [MnO4-]2 [H+]8 } at 25 C

for solids and liquids , activity ~ 1.

Ecell = 1.81 V - (0.0592 V /6) log { [Pb2+]3 / [MnO4-]2 [H+]8 } = 1.81 V - (0.0592 V /6) log { [0.21]3 / [1.4]2 [1.5]8 }

Ecell = 1.81 V - ( -0.22 )

Ecell = 2.03 V

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Answer 2

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