Question

Combining 0.315 mol Fe,0, with excess carbon produced 18.2 g Fe. Fe,0, +30 +2Fe + 3 CO What is the actual yield of iron in moles? mol actual yield: What is the theoretical yield of iron in moles? theoretical yield: What is the percent yield? percent yield:

Answer 1

1)

Molar mass of Fe = 55.85 g/mol


mass(Fe)= 18.2 g

use:
number of mol of Fe,
n = mass of Fe/molar mass of Fe
=(18.2 g)/(55.85 g/mol)
= 0.3259 mol
Answer: 0.326 mol

2)
From reaction,
Mol of Fe produced = 2*mol of Fe2O3 reacted
= 2*0.315 mol
= 0.630 mol
Answer: 0.630 mol

3)
% yield = actual yield * 100 / theoretical yield
= 0.326 * 100 / 0.630
= 51.7 %

Answer: 51.7 %