Question

Combining 0.322 mol Fe,, with excess carbon produced 10.3 g Fe. Fe, 0, +3C — 2Fe + 3 CO What is the actual yield of iron in moles? actual yield: What is the theoretical yield of iron in moles? theoretical yield: What is the percent yield? percent yield:

Answer 1

Actual yield in moles :

1 mol Fe2O3 gives 2 mol Fe

0.322 mol Fe2O3 gives= 2x0.322/1= 0.644 mol Fe

Theoretical yield:

0.322 mol Fe2O3 (2 mol Fe/1 mol Fe2O3)( 56 g Fe/1 mol of Fe)= 36.06 g = 36.06/56= 0.643 mol

% yiled= actula yield x100/thereotical yield

= 10.3x100/36.06

= 28.5%