Question

Q&A CH2630 LB (5 points) Name: Given the information in Table 1 below, calculate the concentrations of each species to complete Table 2 Iron(III) nitrate and KSCN are initial concentration values, while the concentration of FeSCN is after the reaction is complete. As the concentration of Felis significantly larger than that of SCN, the reaction conditions depicted are non-equilibrium. Since there is a large excess of one reactant, the concentration of FeSCN2+ is dependent upon the limiting reactant. This is important, because you will need to know the concentration of FSCN3+ to generate a Beer's Law graph. Show work for full credit. Fe++SCN- = Fe(SCN)+2 Reaction 1 Tolle: Rawatan l Newind ) Test Tube Volume of 0.200 M Fe(NO3), (m.) Volume of 1.00x10-5 M KSCN (ml.) Volume of H 0 (ml.) Total Volume (ml.) А 10.00 1.00 9.00 20.00 10.00 2.00 8.00 20.00 3.00 20,00 10.00 10.00 7.00 6.00 10.00 20.00 Ε 10.00 0,00 20.00 C : 0.2001 - 0 . Talde 2. Species Construtivas () 0.2 : 0.02L Test Tube [Fe(NO), initial [KSCN) initial [FeSCNP after SUN: Il reaction Nom w1 - 6.004 mol

Answer 1

A) moles of iron nitrate = 0.2*10 = 2 millimole

moles of KSCN = .001 * 1 = .001 millimole

total volume = 20 ml

0.001 milli mole of KSCN will react to form .001 millimole of FeSCN

concentration of FeSCN = (.001/1000)/( 20*1000) = .00005 M

B)

moles of iron nitrate = 0.2*10 = 2 millimole

moles of KSCN = .001 * 2 = .002 millimole

total volume = 20 ml

0.002 milli mole of KSCN will react to form .002 millimole of FeSCN

concentration of FeSCN = (.002/1000)/( 20*1000) = .0001 M

C)

moles of iron nitrate = 0.2*10 = 2 millimole

moles of KSCN = .001 * 3 = .003 millimole

total volume = 20 ml

0.003 milli mole of KSCN will react to form .003 millimole of FeSCN

concentration of FeSCN = (.003/1000)/( 20*1000) = .00015 M

moles of iron nitrate = 0.2*10 = 2 millimole

moles of KSCN = .001 * 1 = .001 millimole

total volume = 20 ml

0.001 milli mole of KSCN will react to form .001 millimole of FeSCN

concentration of FeSCN = (.001/1000)/( 20*1000) = .00005 M

D)

moles of iron nitrate = 0.2*10 = 2 millimole

moles of KSCN = .001 * 4 = .004 millimole

total volume = 20 ml

0.004 milli mole of KSCN will react to form .004 millimole of FeSCN

concentration of FeSCN = (.004/1000)/( 20*1000) = .0002 M

E) zero KSCN added so no FeSCN formed .