Question

QUESTION 4 How many millimoles (mmol) of H 30 * are in the acid solution at the beginning of the titration before any base is added? Type your numerical answer (no units!) in the box provided. QUESTIONS The titration curve for this strong acid-strong base titration is provided on the first page of the "Titration Curves for Prelab Assignment" handout. Based on this titration curve, what is the pH at the equivalence point of the titration? Type your numerical answer (no units) in the box below. ExpoPrelab Titration Curves.pdf QUESTION 6 Use the "Strong Acid-Strong Base Titration Curve to estimate the volume of added base in ml) required to reach the equivalence point. Type your numerical answer (no units) in the box provided.

Answer 1

3-

The neutralization reaction between HCl and NaOH is-

HCl + NaOH ---------> NaCl + H2O

that means 1 mole of HCl will neutralize 1 mole of NaOH.

Now given before start of titration,

pH of the solution = 1.02

Again we know

pH = -log [H3O+]

So

[H3O+] = 10-pH  

= 10-1.02  

=  0.095 M

= 0.095 mole/L

= 9.5 * 10-2 mole/L

4-

Now given volume of HCl taken = 25 mL

So we can say volume of H3O+ present = 25 mL  

Because HCl is a strong acid and it will dissociate completely to H3O+ . So what ever the values for HCl can be exactly taken for that of H3O+

Again calauclated concentration of H3O+ = 9.5 * 10-2 mole/L

So moles of H3O+ present = concentration * volume

= 9.5 * 10-2 mole/L * 25 mL  

=  9.5 * 10-2 mole/ 1000 mL * 25 mL  

= 0.002375‬ moles

So milimoles of H3O+ present = 0.002375‬ moles * 1000

= 2.375‬ milimoles

For further calculations, no titration curve is provided.