Question

Question 17

A solution is prepared by dissolving 45 g sodium carbonate, Na₂CO₃, in enough water to make 200 mL of solution. If the density of the solution is 1.1094 g/mL, what is the % mass of the solution?

Question 18

Calculate the molarity of a 4.628 m solution of Sr(NO₃)₂ in H₂O. The density of this solution is 1 g/mL

Include units.

Question 19

What is the molarity of a sodium chloride solution prepared by diluting 2.1 mL of 40 M NaCl to a total volume of 1 L?

Question 20 pts

How many grams are needed to prepare 550 mL of a 0.75 M KNO₃ solution?

Input your numerical answer without units.

Answer 1

0.17) mass of Na,co - 459 volume of Solution - 200 m density of solution 111094 g/ml a mass of solution - density x volume. = 11094 8lmx 200 ml - 2210889 mass of solute x100x 7. Mass = mass of solution 458 x 100% 221.88 g = 20.281.7. 0.18) molality of SY(NO3), - 41628 means 44.628 mol of Sr(NO), is present in 1000 g of V H2O mass of Sy(NO), - molex Mw = 4:628 ml x 211163 g/mol = 79.424 9. so total mass of solution = mass of solute + mass of solvent Il 979.4249 + 1000g = 1979.4249 solution = 19/ma density of volume of solution - 1979.424 mle i molex 1000 : molarity of Sr (NO3)2 - volume of solution (inme 4,628 mol x 1000 mL = 2.338M - 1979.426 m) C Scanned with CamScanner

Q.19) Initial molarity of Nace (M.) = 40m Initial volume (V) = 211 me final volume (Ve) = 11 = 1000 me let final molarity be Mi We know that in dilution mole of solute does not change. Myvi – M₂ V2 =) 40MX 2.1 ml = M2 x 1000 ml M = 40x2.1 M 1000 = 0.084M so final molarity of Nach = 0.084 M .20). molarity of KNO, -0.75 M volume of KNO solution = 550 ml = 0.55L . mol of KNO,: molarity x volume lin ) - = 0.7 MX O.STL 0.4125 mol e mass of KNO₃ required= mol x Mw = 0.4125 mol x 101.1 g/mol = 41.703759 ~ 41,704 g ned with CamScanner