Question

0.08206 Latm.mol-1. K-1 3 J = 1 L atm Question 2 A system releases 55 J of heat while performing 36 J of work. What is the ch

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ane Energy released 55 J q = -555 W=-36] U = qtw U= -55+ (36) & -91J Internal energy decreased by -915.

Add a comment
Know the answer?
Add Answer to:
0.08206 Latm.mol-1. K-1 3 J = 1 L atm Question 2 A system releases 55 J...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An external pressure of 2.00 atm causes a gas to compress by 20.0 L. In the...

    An external pressure of 2.00 atm causes a gas to compress by 20.0 L. In the process of compression, the gas releases 1200 J of heat to the surroundings. What is the change of the internal energy of this gas? 1 atm = 101325 Pa, 1 L = 0.001 m3 .

  • An external pressure of 4.00 atm causes a gas to compress by 10.0 L. In the...

    An external pressure of 4.00 atm causes a gas to compress by 10.0 L. In the process of compression, the gas releases 1200 J of heat to the surroundings. What is the change of the internal energy of this gas? 1 atm = 101325 Pa, 1 L = 0.001 m . (A) +5253 J (B) +2853 J (C) −1605 J (D) −2853 J (E) −5253 J

  • The gas in a piston (defined as the system) is warmed and absorbs 655 J of...

    The gas in a piston (defined as the system) is warmed and absorbs 655 J of heat. The expansion performs 348 J of work on the surroundings. Part A What is the change in internal energy for the system? ΔE = J A system releases 617 kJ of heat and does 145 kJ of work on the surroundings. Part A What is the change in internal energy of the system? ΔE = kJ A 31.2 g wafer of pure gold...

  • A system undergoes a process consisting of the following two steps: Step 1: The system absorbs...

    A system undergoes a process consisting of the following two steps: Step 1: The system absorbs 27 J of heat while performing 53 J of work. Step 2: The system releases 53 J of heat while 27 J of work is done on it. Calculate the total energy change for the overall process. Does the system gain or lose energy in the process?

  • R = universal gas constant = 0.08206 L *atm/mol *K 3. (6 pt) Use this information...

    R = universal gas constant = 0.08206 L *atm/mol *K 3. (6 pt) Use this information to answer the following three questions: You have 2.05 mol of nitrogen gas in a flexible, sealed 420 mL container at room temperature (25°C) that has an internal pressure of 542 mm Hg. a. The volume of the container is expanded to 560. mL. What is the new pressure of the container? b. The container is heated to 60°C, what is the new pressure...

  • QUESTION 10 A system releases 7 J of heat. And the same time 12 J of...

    QUESTION 10 A system releases 7 J of heat. And the same time 12 J of work is done on the system by the surroundings. What is the AU? 05 -13) 8) 07) O-36) -131 QUESTION 11 A system absorbs 41 of heat. And the same time the system does 6 J of work on the surroundings. What is the AU? O-9) -39) 35 ) 11) 14 ) -15) QUESTION 12 A system absorbs 8J of heat. And the same...

  • 1. A system releases 654 kJ of heat and does 140 kJ of work on the...

    1. A system releases 654 kJ of heat and does 140 kJ of work on the surroundings. What is the change in internal energy of the system? 2. How much heat is required to warm 1.30 L of water from 26.0 ∘C to 100.0 ∘C? (Assume a density of 1.0g/mL for the water.) Express your answer using two significant figures..

  • 1. Acetone has a heat capacity at constant volume of 61.50 J/mol K at 310 K...

    1. Acetone has a heat capacity at constant volume of 61.50 J/mol K at 310 K when it is in the gas phase. Consider the system where 1.500 moles of acetone is placed in an adiabatic chamber at 330.04 K. It is allowed to expand such that during the expansion the temperature drops to 288.05 K. Calculate the work done and the change in internal energy for the system. Assume the heat capacity is constant over this temperature range. (ANS:...

  • Please just answer Part 2 The vaporization of 1 mole of liquid water (the system) at 100.9°C, 100 atm, s endothermic. H0HOg) Assume that at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of l...

    Please just answer Part 2 The vaporization of 1 mole of liquid water (the system) at 100.9°C, 100 atm, s endothermic. H0HOg) Assume that at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 mL and 30.62 L, respectively 5th attempt d See Periodic Table See Hint (0.5 point) Part 1 Calculate the work done on or by the system when 1.85 mol of liquid H20 vaporizes. 5736.23319:J (0.5...

  • A container of 3.1 mol of gas expands from 1.5 L to 2.5 L (1 L...

    A container of 3.1 mol of gas expands from 1.5 L to 2.5 L (1 L = 0.001 m3) while the pressure is kept constant. The gas is initially at a temperature of 280 K. What is the pressure of the gas? 4811034 Pa What is the final temperature of the gas? T 466 What is the magnitude of the change in internal energy of the gas, and is the internal energy increasing or decreasing? (Note that there is no...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT