Question

calculate the appropriate amount of solid KHP (MM = 204.22 g/mol) that should be added to...

calculate the appropriate amount of solid KHP (MM = 204.22 g/mol) that should be added to a clean, dry and labeled 125 mL Erlenmeyer flask so that it takes about 10 mL of the approximately 0.1 M NaOH to perform the titration.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

NaOH + KMP Nakp + Ho Imal of NaOH reacts with Imal kHP moles of NaOH - Molarity XVolume - Olmol/L x 0.01L = 0,ool mal - wоu

Add a comment
Know the answer?
Add Answer to:
calculate the appropriate amount of solid KHP (MM = 204.22 g/mol) that should be added to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL...

    In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL of DI water and titrate the sample with 0.10 M NaOH. Calculate the volume (to the nearest mL) of NaOH required to reach the equivalence point. a) 3 ml b) 15 ml c) 20 ml d) 30 ml e) 100 ml

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • Problem: A 1.523 gram sample of KHP (molar mass=204.22 g/mol) was dissolved in 20.00 mL of...

    Problem: A 1.523 gram sample of KHP (molar mass=204.22 g/mol) was dissolved in 20.00 mL of distilled water. Titrating this solution to the phenolphthalein end point required 15.30 mL with the NaOH solution. The balanced titration reaction is as follows: NaOH(aq) + KHC4H8O4(aq) -> KNaCgHO(aq) + H2O(1) Calculate the molarity of the NaOH solution. Show your work.

  • Calculate each Ka using the information below. Acid Used: KHP Molar Mass of Acid: 204.22 Amount...

    Calculate each Ka using the information below. Acid Used: KHP Molar Mass of Acid: 204.22 Amount of KHP used: 1.04 g Initial (mL) 0 2 4 6 8 10 Final (mL) 2 4 6 8 10 10 Amount Added (mL) 2 2 2 2 2 - pH 4.24 4.27 4.30 4.46 4.51 4.63 Ka

  • (Answer from question 4) HP− + H2O is in equilibrium with P2− + H3O+ This axid...

    (Answer from question 4) HP− + H2O is in equilibrium with P2− + H3O+ This axid will attack the base Assume 1 mol of KHP will neutralize 1 mol of NaOH V = 25 ml M = 0.1M Mol Acid = mol Base Mol base = M*V = 25 ml ^0.1 M = 2.5 mmol of base therefore, you need 2.5 *10^-3 mol of acid, that is mol of KHP Since KHP = 204.22 g/gmol mass = mol*MW = 2.5*10^-3...

  • As part of Lab 11 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH an...

    As part of Lab 11 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH and dissolve it into 100.0 mL of water. You then measure 0.1993 g of KHP (204.22 g/mol) and place it in a clean, dry 100-mL beaker, and then dissolve the KHP in about 25 mL of water and add a couple of drops of phenolphthalein indicator. You titrate this with your NaOH(aq) solution and find that the...

  • The titration of 0.9659 g of KHP (molar mass = 204.227 g/mol) requires 49.35 mL of...

    The titration of 0.9659 g of KHP (molar mass = 204.227 g/mol) requires 49.35 mL of NaOH solution What is the concentration of the NaOH solution? concentration: apling Learning, Inc. about us Careers privacy policy terms of use contact us help

  • A 40.0 mL solution containing 0.500 g of KHP was titrated with NaOH solution of unknown...

    A 40.0 mL solution containing 0.500 g of KHP was titrated with NaOH solution of unknown concentration, and the pH of the solution was measured after each known amount of NaOH was added. (KHP=potassium hydrogen phthalate; formula=KHC8H4O4; molar mass=204.22 g/mol). The acid base reaction occurs according to the following net ionic equation: HC8H4O4- (aq) + OH- (aq) ®C8H4O42- (aq) + H2O What is the molar concentration of KHP in the solution? If the titration required 24.0 mL of NaOH to...

  • please help me speciqlly with 11. 12. 13. 14   Experiment 7, Analysis of KHP by titration...

    please help me speciqlly with 11. 12. 13. 14   Experiment 7, Analysis of KHP by titration with NaOH Wright College, Department of Physical Science and Engineering In this experiment, you will determine the amount (percent) of potassium hydrogen phthalate (KHP) that is in an impure sample. You will determine the percent of KHP via titration using NOH with known inolarity. The reaction will follow, KHCgH00, (aq) + NaOH (aq) ---------> KNaCHO, (aq) + H20 (I) At the end point, the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT