Question

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QUESTION 3 4.(9 points) Consider 0.333 mL of an ideal gas initially at 44.00 °C in a sealed container. What is the final volume after the gas is heated to 100.00 °C at constant pressure? Report your answer in mL with three decimal places. QUESTION 4 7.(7 points) What is the total pressure of a gas mixture composed of 0.622 atm He gas, 844 torr Ne gas and 378 mmHg Ar gas? Report your answer in torr, rounded to a whole number, Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close Windo o Type here to search e *10 . ©

Answer 1

Young - 0. 333 ML or 0.333 Litoe 1000 T: 44 or 317 K 073+ 44 K = 373 k. TA = 100°c or - pr=ART using ideal Gas equation : nep Constant = n (sealed Containes) i = Constant. Vf = rix Tf = 0.333 mL x 343 K o. 333 mL X 373K Ti 317 K ☺ w = 0.392 mb. Asing dalton's Law of partial pressure: P total. = E(Partial pressure of gas c) All the gases are inert gases, there will be no interaction... : Total pressure will be sum of partial pressure of each gates Protal = PHet Pne t Par = 0.609 29 atm + 844 torr + 378 mm Hg NOTE : 1 toir = tó atm I mm Hg = atm). 760 378 atm = 0.622 atm t 844 atm + = 9.099 atm 760 760 Ptotas sin torr = 0.00099 x 760 torp, 1695 torr.