Question

From the following balanced equation, 4 NH3(g) + 50,(9) — 4 NO(g) + 6H20(1) how many moles of H,O can be formed when 4.0 mol NH, react with 4.5 mol 0,? Select the correct answer below: O 4.0 mol O 4.5 mol O 5.4 mol O 6.0 mol

Answer 1

Answer (1) Given balanced Chemical equation in 4 Nuts Los + 56218) -> 4N019) + 8 HE DLL Here 4 moles of NH3ig reacts with 5 moles of Oscg, and gives 6 moles of H₂O H If &moles of NH3(g) neacts with 405 moles of Oz (as then I we know that 5 moles of Oz (8) gives 6 moles of H₂011) I moles of oocer gives moles of Hellas so 415 moles of 0219) gives + 6 x 415 moles of Helly Hence with 564 mol of H₂O 45 mol Dz. > can be formed 5.4 moles of H₂ 018) when 4:0 mol Nis sealt - Answer ♡ given moles of Cq H6 = 360 mol molecular mass of CqH6 = (2x = 24+6 +(6x) = 30 g/mol we know that moles of mass Cath = of Cq Ho in gram molecular mass of CQHh 3:80 mal = mass of whe 30 g/mol mass of Ca Mo = 3.80 mol x so gmoi mass of Cate = 11487

MAIS UM DRE Answer ® Given balanced chemical reaction in 2 He (8) + O219) 240 (d) Mene weight of Oz (d) taken = 5:58 g molecular mass of Oz (0) = 32 g/mol moles of g = weight of O2 molecular mass of Og 5.58 g 32 g/mol 0174375 mol mol of Delo) = Forom balanced reaction we see that one mol of O2 (91 produced - 2 moles of H2O (4) Mence 0.174375 mol Oq poroduced → 27 0174375 mol H₂O again. moles 034875 mol H₂O of Hoo = mass of M20 porodured moleculen mapp of H₂O 0.34875 mol = mass of H₂O foomed ! 18 g/mol mass of H2O formed = 0: 34875 mol x 18 gmot mence Theoretical yield of H2O = 6 2775 g given actual yield of H₂O = 3128 g

whese TIETY pencent yield Actual yield of H₂O = X 100 Theoretical yield of He De 3:28 g 6. 2775 I = 0.5225 XiDo = 52.25 % = 52.2 % percent yield Answeg [ Given balanced Chemical reaction is 3 Ca(OH)2 + 243804 → Caz (PO4), + 6H₂O From this reaction we see that 6 moles of HRD generated by → 3 moles of Caloyle I so I mol of Hel generated by 3 moles of Calon): Hence 70p moles of Hp O generated by → 3x7.00 moles of Caloy) - 3150 moles of Ca Comba Hence 3.50 moles of calcium hydroxide are needed to generate 700 moles of water.