Determine the theoretical yield of alum (MM=474.38), to two decimal places, if 0.46 g of aluminum (MM = 26.98 g/mol) are reacted.
0.46 g of aluminum (MM = 26.98 g/mol) reacted :
moles of Al reacted : 0.46 g / 26.98 g/mol = 0.017 moles
Alum : KAl(SO4)2·12H2O , MW : 474.38 g/mol
1 mol Al ===> 1 mol KAl(SO4)2·12H2O
thus, theoretical yield of alum :
= 0.017 moles *474.38 g/mol = 8.088 g ~ 8.1 g ( 2 significant No. )
Determine the theoretical yield of alum (MM=474.38), to two decimal places, if 0.46 g of aluminum...
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