Question

1. What pressure is exerted by 4.00 g of Ne gas at 25.00 ^oC inside a 865 mL container, assuming ideal gas behavior?

2. A sealed container is holding 328 torr of N₂ gas, 489 torr of O₂ and 371 torr of H₂. What is the total pressure inside the container in units of torr?

3. A gas mixture composed of He and Xe is maintained at STP. If the mixture contains 0.73 atm of He, what is the partial pressure of Xe in the unit atmospheres?

Answer 1

1) Given, hoof holes of Ne = 4 20.17 o Ne= 0,198 wol N2 I=25°c = 298.15k, v=865 ml = 0,865L So By itzal gas equation, et PV = HRT P = 0.198 x 0.0821 x 298.15 0.865 into = s.603 atm 2) Given, Prz = 328 toor, Po = 489 toro PH = 371 tour 1 = Total preswe= 328 + 489 +371 total = 1248 tour 3) since the gas mixture is at STP. So, Ptotal = lath, If He = 0.73 ath, Then, Pxe = Ptotal-Phe = 1-0.73 Pxe = 0.27 atm at STP