

I Carugate the standard enthalpy of formation Of US 2 (AtH) from its elements. Given that:...
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7- (15 pts) Calculate the standard enthalpy of formation of CS,() given that AH 393.5 kJ/mol AH- 296.4 kj/mol a. C(s) Oz(g) COlg) b. S(s) O,(g). SOlg) c. CS)()30 (g) CO,(B ) + 2SO;(g) + AH° -1073.6 kj/mol (the standard state of the element Sulfur is S(s)
7- (15 pts) Calculate the standard enthalpy of formation of CS2 (1) given that a. C(s) + O2(g) + CO2(g) b. S(s) + O2(g) → SO2(e) C. CS2() + 302(g) → CO2(g) + ' 250 (6) AH° = -393.5 kJ/mol AH° = -296.4 kJ/mol AH° = -1073.6 kj/mol (the standard state of the element Sulfur is S(s))
Calculate the standard enthalpy of formation of CS2() given that AH=-393.5 kJ/mol AHo = -296.4 kj/mol a. C(s) + O2(g) CO2lg) b. S(s) +O2(g). SO2(g) AH = -1073.6 kj/mol C. CS2(I)+302(g) Co2lg) + 2S02(B)
The standard heat of formation, ΔH∘f, is defined as the enthalpy change for the formation of one mole of substance from its constituent elements in their standard states. Thus, elements in their standard states have ΔH∘f=0. Heat of formation values can be used to calculate the enthalpy change of any reaction. Consider, for example, the reaction 2NO(g)+O2(g)⇌2NO2(g) with heat of formation values given by the following table: Substance ΔH∘f (kJ/mol) NO(g) 90.2 O2(g) 0 NO2(g) 33.2 Then the standard heat...
The standard enthalpy of formation of gaseous water from its elements is -241.8 kJ/mol. H 2(g) + ½ O 2(g) → H 2O(g) What is the enthalpy change when 3 moles of hydrogen form?
Calculate the standard enthalpy change, ΔH, for the formation of 1 mol of strontium carbonate (the material that gives the red color in fireworks) from its elements. Sr(s) + C(graphite) + 32 O2(g) -----> SrCO3(s) The information available is: (1) Sr(s)+ 12O2(g) ---->SrO(s) DeltaH= -592kj (2) SrO(s) + CO2(g) -----> SrCO3(s) DeltaH= -234kj (3) C(graphite) + O2 (g) ----->CO2 (g) DeltaH= -394kl
The reaction that represents the standard enthalpy of formation for benzene (C6H6) is: O CoH6() +6 C(graphite) + 3 H2(g) O 6 C(graphite) + 6 H(g) → C6H6(l) O 6 C(diamond) + 3 H2(g) - C6H6(1) O C6H6(0) + 15/2O2(g) →6 CO2(g) + 3 H2O(g) O 6 C(graphite) + 3 H2(g) → CoH60)
Part A:
Write an equation for the formation of NO(g) from its elements
in their standard states.
Express your answer as a chemical equation. Identify all of the
phases in your answer.
Part B:
Write an equation for the formation of BF3(g) from its elements
in their standard states.
Express your answer as a chemical equation. Identify all of the
phases in your answer.
Part C:
Write an equation for the formation of C6H6(l) from its elements
in their standard...
rd enthalpy of formation for compound WC(s) from Wis) and Clgraphite) is difficult to measure directly because the reaction occurs at 1400°C w(s) + C(graphite) → WC(s) H combustion of the elements and of tungsten carbide can be measured and are given b However, the heats of 2w(s) + 302(g) → 2W03(s) C(graphite) + O2(g) → CO2(g) 2wc(s) + 502(g) → 2W03(s) + 2CO2(g) Δ H =-1680.6 kJ Δ H =-393.5 kJ Δ H =-2391.6 kJ Use Hess law and...
Using heat of formation values from Appendix C of the textbook, calculate the standard enthalpy change for the following reaction: 2 C3H8 (g) + 9 O2 (g) ----> 2 CO2 (g) + 8 H2O (l) + 4 CO2 (g) Enthalpies of formation values C3H8 (g) = -103.85 kJ/ mol , O2 (g) = 0 , CO (g) = -110.5 kJ/ mol , H20 (l) = -285.83 kJ/ mol , CO2 (g) = -393.5 kJ/ mol