2. A diploid yeast was ABD on one chromosome and abd on the other. The yeast...
2. A diploid yeast was ABD on one chromosome and abd on the other. The yeast cell underwent meiosis and the four genomes in the resulting tetrad were analyzed and determined to be: ABD, ABD, aBD and abd.
a. For the moment, focus on the outcome regarding the number of B versus b genes? (Ignore D and d.) What is unexpected, regarding the number of gene types in the meiotic cells? Rationalize how this could have happened, assuming that this outcome had something to do with recombination.
b. Is there a second “unexpected” outcome, and, if so, what is it? Assume that this second outcome occurred in a process that was linked to the first outcome, which happened with the B/b gene. Explain how they both might have occurred together
c. What is the name associated with the outcome: ABD/ABD/aBD/abd?
There is a comment regarding needing more knowledge, but I'm not sure what else you would need to answer this question other than a background in genetics.
Homework Answers
Ans
2.(a) recombination between homologous chromosome.
(b) ABd,abD,aBD,aBd,abD
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2. A diploid yeast was ABD on one chromosome and abd on the
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Problem:
Yeast chromosome 3 has these genes in this order: HIS4 LYS1 URA3
ADE2. You have created a diploid strain of this genotype:
You sporulate the diploid and analyze tetrads. Most tetrads show
2:2 segregation for all markers and recombination frequencies that
are consistent with the established genetic map. However, you
notice the one strange tetrad indicated below:
Your goal is to explain how the genotypes of this tetrad arose
during meiosis:
a. Do these spores indicate that...
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please help and thank you
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