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Here is a genetic map of four loci on the same chromosome; what is the probability...

Here is a genetic map of four loci on the same chromosome; what is the probability of a triple crossover between them?

A---2cM—B—3.5cM—C—1cM-----4.5cM---D

a. 0.315

b. 0.00315

c. 3.15 x 10-3

d. 3.15 x 10-7

e. None of the above

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Answer #1

For the obtaining triple cross over from above data we need to multiply all the distance between the loci.. With all the progeny.

As -

Distance from A to B multiplied with distance from B to C multiplied with distance from C to D.

If we assume that there are total number of progeny 100 then

Triple Cross over will be -

.02 × .035 × .01 × .45 × 100 = .0315

This number absent in all five given options.

Hence when we assume there were 100 progeny then e option will be correct ( non of the above)

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