Question

A sample of an oxide of antimony(sb) contained 39.50 of antimony (sb) combined with 13.0g of oxygen (O) what is the simplest formula for the oxide compound that forms?

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Answer 1

Answer :

Atomic weight of Antimony - 121.760

So number of atoms in 39.5 units

= 39.5 ÷ 121.760

= 0.3244121.760 ATOMS

[Here we need only ratio. So units like mole, gram etc are irrelevant.]

Atomic weight of oxygen - 15.99

So oxygen atoms in 13 units

= 13 ÷ 15.99

= 0.813 ATOMS

So % of antimony atoms = 0.3244 ÷ 1.1374

= 29%

% of oxygen atoms = 0.813 ÷ 1.1374

= 71%

So simplest attributable formula is

Sb3O7