Question

light microscou What is the formula to determine numerical aperture? NA=nsina Calculate the resolution of a microscope's objective where = 60° and n=1 and the wavelength of light was 600nm? What would the resolution be if an electron scope was used (electron wavelength = 0.004nm)? Show your work. 0.610 0.61 640 3667 NA = 4,22 6x 10 0.611 nono IsinGoo 0,8660 nsina 7 Goonm 76x10 m Question 4: Short answer responses. sinids discussed in class?

I would just like to know if I got the first part right.

Answer 1

The numerical aperture (NA) can be calculated by the formula given below:

   ...... (1)

NA= n sind

Here,

'n' is the refractive index of the medium between the object and the objective lens.

'$\theta$' is half the angular aperture of the objective lens.

The resolution (r) of the microscope's objective can be calculated by the formula given below:

...... (2)

r = 0.61 NA

Substitute equation (1) in equation (2) as shown below:

   ...... (3)

T = 0.61 nsin

Substitute the data given in the formula as shown:

T = 0.61X nsin 1 0.61 x 600 x 10-9 -= 2 x 0.61 x 600 x 10-9 = 7.32 x 10- 1 x sin 60 e

Therefore, is the resolution of the microscope's objective.

7.32 x 10-7

Calculate the resolution of the electron scope by substituting the data given in the question in the equation (3) as shown below:

0.612 T = 1 0.61 x 0.004 x 10-9 - = 2x0.61 0.004 x 10-9 = 4.88 x 10-12 1 x sin 60

Therefore, is the resolution of the electron scope.

4.88 x 10-12