var p = var g + var e
p - phenotype , g - genotype , e - environment
HERD 1 : 110 = var g + 12
var g = 110 - 12
= 98
HERD 2: 110 = var g + 12
var g = 98
a) HERD 1
Broad sense heritibility = variance of genotype / variance of phenotype
= 98 / ( 110)
= 0.89
Narrow sense heritibility = additive genotypic variance / variance of phenotype
= 15 / (110)
= 0.13
HERD 2
Broad sense heritibility = variance of genotype / variance of phenotype
= 98 / 110 = 0.89
Narrow sense heritibility = additive genotypic variance / variance of phenotype
= 35 / 110
= 0.31
b) HERD 1 i recommend because it has low narrow sense heritibility . i.e, it have only low level of resemblance to the parents. So, more variability is present. Enabling to produce much variable new variety.
genetics: please answer as best you can and explain! this was all the info I was...
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please help with this assignment. please help answer
all and explain your answers. if you do I'll be sure to give a
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