the plasmid carries the functional lac I gene and lac operon.
mutant 1 does not express the beta-galactosidase in the presence or absence of the lactose, so the mutation may be in the beta-galactosidase gene or in the promoter if the promoter is mutated the genes in the lac operon can not be transcribed, in the merodiploid, the beta-galactosidase is expressed in the presence of lactose similar to wildtype so the genotype of the mutant 1 is lacI+ lacP+ lacO+lac Z-
or lacI+lacP-lacO+lacZ+
mutant 2, the beta-galactosidase is not expressed in any of the conditions, even in the merodiploid, so components from the lac operon in the chromosome inhibit the expression of the lac operon in the plasmid, lac Is codes for super repressor, which inhibits the expression of the lac operon by binding to the lac operator even in the presence or absence of the lactose.
the genotype of mutant 2
lac Is lacP+ lacO+ lac Z+
mutant 3 expresses lac operon in all conditions which means the lac operon in the chromosome has constitutive operon which cannot be inhibited by the lac repressor.
genotype of mutant 3.
lac I+ lac P+ lacOc lac Z+
A meroploid is constructed for each of the three strains. The plasmid carries a wild type...
Three different strains of E. coli carry a mutation in the lac operon and/or laci gene. The production of B-galactosidase (+ present or - absent) is measured when lactose is present and absent from the medium. Assume the mutations involve only 1, 0, or Z. A merodiploid is constructed for each of the three strains. The plasmid carries a wild type lac operon and lacl gene. The production of functional B-galactosidase (+ present or - absent) is measured when lactose...
The genotypes of the lac operon of several haploid and
partial diploid E. coli strains are given. For each genotype,
indicate the status of B-galactosidase synthesis as either Yes or
No. Assume that no glucose is present and cAMP is rich in the
growth medium.
• Oc is a mutant operator that cannot be bound
by the wild type repressor protein.
• Is is a mutant of repressor gene and cannot
bind to operator
Haploid Partial Diploid IOZY IOCZY ISOZY...
As a student project, you have isolated six new mutant strains
of E. coli with altered behavior of the lactose operon. The strains
are listed in the table below, together with their phenotypes (with
regard to significant ?-galactosidase synthesis) in three specific
situations.
Columns 1 and 2 present the phenotypes of each mutant haploid
strain. In column 1, the mutant is in an otherwise wild-type
genome. In column 2, the genome also carries a nonsense-suppressor
mutation (that is not present...
In this problem you will explore how to solve problems involving partial diploid lac operon bacterial strains. Bacterial strains that are "partially diploid" have two copies of the lac operon because they aquired a plasmid carrying just the lac operon region. One copy of the lac operon region is on the recipient's bacterial chromosome, and the other copy is on the P plasmid that was introduced into the cell by conjugation. Partial diploid genotypes are written with the P segment...
The lac operon in E. coli is a well-studied gene system, and
β-galactosidase (β-gal) is the product of the lacZ gene. The
diploid conditions represent the addition of a plasmid carrying
different components of the lac operon. Determine if β-gal will be
generated under the conditions. Assume that glucose is absent. A +
in the genotype indicates a functioning gene, while a – indicates a
loss-of-function allele. The OC is an operator mutant that cannot
bind the lacI protein. Use...
There are two different strains of E. coli. One type is a wild type and the other is a lac operon mutant. The lac operon wild type has the genotype: I+P+O+Z+Y+A+ What is a silent mutation? What would be the result for the lac operon genes?
The lac operon contains a DNA sequence known as the lac promoter (P or P+ for wild type; P– for mutant (RNA polymerase does not bind)) that serves as the RNA polymerase binding site. The lac operon also contains a DNA sequence known as the Lac operator (O or O+ for wild type; O– or Oc for mutant (lac repressor cannot bind)) which is the binding site for lac repressor. The lac repressor, a protein, is encoded by the lac...
Shown below are relevant genes and sites from various E. coli strains. Note: + designates the wild-type gene or site that is fully functional, and - designates a deletion of that gene or site; lacot means all operators (01, O2 and 03) are functional; assume all other genes and sites not listed are wild-type and functional (including lacA). In some cases, a plasmid containing a wild-type functional gene or site was transformed into the E. coli strain. The strains were...
Shown below are relevant genes and sites from various E. coli strains. Note: + designates the wild-type gene or site that is fully functional, and – designates a deletion of that gene or site; lacO+ means all operators (O1, O2 and O3) are functional; assume all other genes and sites not listed are wild-type and functional (including lacA). In some cases, a plasmid containing a wild-type functional gene or site was transformed into the E. coli strain. The strains were...
In this problem you will explore how to solve problems involving partial diploid lac operon bacterial strains. Bacterial strains that are "partially diploid" have two copies of the lac operon because they aquired a plasmid carrying just the lac operon region. One copy of the lac operon region is on the recipient's bacterial chromosome, and the other copy is on the F' plasmid that was introduced into the cell by conjugation. Partial diploid genotypes are written with the F' segment...