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In a wild-type carnivorous plant, protein X is encoded by a haplosufficient gene “X”. The X protein normally homodimerizes. The X-X dimer enzymatically catalyzes a biochemical reaction that is critical for the digestion of insects that it traps. XD represents a dominant negative allele, a mutation, of gene X. |
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What would be the predicted phenotype of a plant with the genotype X+/XD ? Which one of these pieces of information allows you to reach that conclusion? |
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| a. |
The plant would be mutant and would not digest bugs, because absolutely no X-X dimers will form in the heterozygote. |
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| b. |
The plant would be mutant and incapable of digesting insects, because X is known to be haplosufficient. |
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| c. |
The plant would be wild type and would be quite capable of bug digestion, because XD is a negative allele. |
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| d. |
The plant would be wild type and would produce the enzyme for digestions of insects, as X is haplosufficient. |
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| e. |
The plant would be mutant and would be incapable of digesting insects, as the mutant allele XD is a dominant allele. |
Ans- Option b is correct- the plant would be mutant and incapable of digesting insects, because X is known to be haplosufficient.
Explanation- Firstly, the plant is mutant because XD gene is present, that is mutant and secondly, it would be unable to digest insects because the gene X is haplosufficient.
In a wild-type carnivorous plant, protein X is encoded by a haplosufficient gene “X”. The X...
In a wild-type fungus, protein E (encoded by the haplosufficient gene “E”) normally homodimerizes, and the E-E dimer catalyzes a biochemical reaction necessary for the production of a dark pigment. ED represents a mutant, dominant, negative allele of gene E. What is the predicted phenotype of a fungus cell of genotype E+/ED, and why? A) mutant (no pigment production), as E is haplosufficient B) mutant (no pigment production), as no E-E dimers will form in the heterozygous C) mutant (no...
Help with both please!
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all XY male offspring will be affected
all female offspring will be affected
half of the offspring will be affected regardless of their
sex
1/4 of the offspring will be affected regardless of their
sex
half of XY male and 1/4 of XX female offspring will be
affected
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5. Consider the wild-type F8 gene. What would happen to the 1)
transcript
(mRNA) sequence and quantity, 2) to the protein (sequence,
quantity, function) and 3) the person’s
overall phenotype if they were homozygous (both copies of the
gene are the same) for a 3 base-pair
deletion in the:
i. First intron
ii. First exon
iii. The promoter
iv. 5’UTR
v. Last exon
6. What environmental factor could affect the phenotype caused
by an F8 null mutation?
Thrombophilia is a...