3. If 50 of the 500,000 people in Atlanta have PKU, how many people are carriers?...
3. If 50 of the 500,000 people in Atlanta have PKU, how many people are carriers?
4. In Atlanta, if a woman with PKU marries a man without symptoms of PKU, what is the chance that they will have a child with PKU?
Homework Answers
Answer:
3).
Frequency of PKU trait = q^2 = 50/500000 = 0.0001
Frequency of PKU allele = q = SQRT of 0.0001 = 0.01
Frequency of normal allele = p = 1-0.01 = 0.99 (as p+q=1)
Frequency of carriers = 2pq= 2*0.99*0.01 = 0.0198
Number of carriers = 0.0198 * 500000 = 9900
4).
PKU = p
Normal = P
Based on the information, the man would be the carrier. Then only the child would have the PKU trait.
pp (woman) x (man) Pp ---Parents
|
P |
p |
|
|
p |
Pp (normal) |
pp (PKU) |
The chance of child with PKU = 50%
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