Complementary sequence would be
a) 3’-CCTAAAAACAGGTGTTAGT-5’
b) 5’-AAGCTCAGGTTCAGCATGAT-3’
I am assuming that 6.7 gm MgCl2 is dissolved in 2.4 L water and we know that molecular mass of this chemical is 95.211 gm/mol
a) The formula for molarity is (M)= number of moles/number of liters (M=# moles/# L)
6.7 gm MgCl2 1000mL (1 mol. MgCl2)
2400mL H20 1L (95.211gm MgCl2)
= 6.7x 1000
2400x95.211
=0.02932 M (So if we dissolve 6.7 MgCl2 in 2.4 L then it will give 0.029 M solution)
b) Molarity can be calculated using following formula
C1V1=C2V2
C1=0.029 M
V1=2.4
C2=?
V21.7
So, 0.029x2.4=C2x1.7
C2= 0.029x2.4/1.7
=0.0409 M, so answer is 0.0409 M
C) again use C1V1=C2V2
C1=0.029
V1=2.4
C2=0.0150
V2=?
V2= C1V1/C2
= 0.029x2.4/0.0150
=4.54 liters
So, correct answer would be 4.54 liters
[Note: Using these simple steps you can calculate any molarity or concentration].
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