Homework Answers
3A)
a) Two genes are involved in flower color. When pure bleeding flowers with pink petals crossed with pure breeding flowers with white petals, F1 progeny is blue.
Let P_bb be the genotype of Pink flower
Let ppB_ be the genotype of White flower
P_bb (Pink) * ppB_ (White)
F1: PpBb (Blue)
Blue has dominant alleles of two genes because when blue crossed with pink, and when blue crossed with white, F1 progeny were Blue
b) Flower color is determined by the genes of the parents.
c) Genotype of Pink flower: P_bb
Genotype of White flower: ppB_
Parents : P_bb (Pink) * ppB_ (White)
F1 progeny : PpBb (Blue)
F1 Cross : PpBb * PpBb
Gametes of PpBb : PB, Pb, pB, pb
Gametes of PpBb: PB, Pb, pB, pb
F2 Progeny :
PPBB (Blue), PPBb (Blue), PpBB (Blue) PpBb (Blue), PPBb (Blue), PPbb (Pink), PpBb (Blue), Ppbb (Pink), PpBB(Blue) , PpBb (Blue), ppBB (White), ppBb ( White), PpBb (Blue), Ppbb (Blue) , ppBb (White) , ppbb (Pink-white)
d) Out of 8, half are white. So genotypes of crossed F2 plants are Blue (PpBb) and White (ppBb)
PpBb (Blue) * ppBb (White)
Gametes of Parent 1: PB, Pb. pB, pb
Gametes of Parent 2: pB, pb
Progeny : PpBB (Blue),PpBb (Blue) , PpBb (Blue) ,Ppbb (Pink) , ppBB (White), ppBb (White), ppBb (White), ppbb (White)
Progeny phenotypic ratio : 3 (Blue) : 1 (Pink) : 4 (White)
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