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can someone please explain this answer through punnett squares? Having troubles understanding the process.
141 In Drosophila, white eyes (w) and yellow body (y) are both recessive X-linked mutations. The wild type alleles, w+ and y+
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Answer #1

both w and y genes are X linked.

genotype of the female who is homozygous for red eyes and yellow bodies is Xw+yXw+y and genotype of the male who has dark body and white eyes is Xwy+Y.

Xw+yXw+y * Xwy+Y.

Xwy+ Y
Xw+y Xw+yXwy+ (female with red eyes and dark body) Xw+yY ( male with red eyes and yellow body)

so phenotype of the F1 progenies is

male: red eyes and yellow body

female: red eyes and dark body

F1 cross

Xw+yXwy+* Xw+yY

Xw+y Xwy+
w+y Xw+yXw+y ( female with red eyes and yellow body) Xwy+Xw+y ( female with red eyes and dark body)
Y Xw+yY (male with red eyes and yellow body) Xwy+Y ( male with white eyes and dark body)

females:

female with red eyes and dark body = number of female with red eyes and dark body/total number of females=1/2

female with red eyes and yellow body = number of females with red eyes and yellow body/total number of females=1/2

males:

male with red eyes and yellow body = number of male with red eyes and dark body/total number of males=1/2

males with white eyes and dark body= number of males with white eyes and dark body/total number of males=1/2

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