Question

0.9 points Consider a population of 100 individuals and the frequency of the Aalele is 0.6 and the frequency of the alle is 04. If the following fitness values for each genotype are applied to the next generation what be the frequency of the A allele in the next generation? WAA1 WA0.25 was 0.25 a o oo

Answer 1

The answer will be option a (0.81).

Explanation:

Now, frequency of AA = (frequency of A)² = (0.6)² = 0.36

Now, frequency of aa = (frequency of a)² = (0.4)² = 0.16

Now, frequency of Aa = 2 x frequency of A x frequency of a = 2 x 0.6 x 0.4 = 0.48

Also, mean fitness = (Frequency of AA x Fitness of AA) + (Frequency of Aa x Fitness of Aa) + (Frequency of aa x Fitness of aa) = (0.36 x 1) + (0.48 x 0.25) + (0.16 x 0.25) = 0.36 + 0.12 + 0.04 = 0.52

So, after selection frequency of AA = (Frequency of AA x Fitness of AA) / mean fitness = 0.36 / 0.52 = 0.692 (Up to 3 decimals)

So, after selection frequency of Aa = (Frequency of Aa x Fitness of Aa) / mean fitness = 0.12 / 0.52 = 0.231 (Up to 3 decimals)

Thus, frequency of A allele in the next generation = Frequency of AA + 1/2 of Frequency of Aa = 0.692 + (0.5 x 0.231) = 0.8075 = 0.81 (Up to 2 decimals)