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Question 4 (10 points) What percent would exhibit the normal phenotype between a cross of aa and Aa (A -normal pigmentation a
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For determining the percentage of individuals exhibiting the normal phenotype , we need to draw a punnett square for the respective cross Aa× aa where 'A' represent normal pigmentation and 'a' represent albinism. Punnett square is shown below:- - Aa x aan - Jalal a aa aa a laaaa AQ - Normal pigmentalion aa - Albinism. Genotype = 1:1 Aai aa. 1: 1 Phenotype = % exhibitiAs albinism is an autosomal recessive disorder so Aa genotype will show normal pigmentation and aa will show albinism.

So the percentage exhibiting normal phenotype is 50%.

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