Question

QUESTION 9 Suppose that in a population the frequency of a particular recessive condition is 1/400. Assume the presence of only a dominant allele (A) and a recessive allele (a) in the population and that the population is at Hardy-Weinberg equilibrium. What is the frequency of heterozygotes in the population? 0.0025 0.05 0.095 0.9025 0.0475 5 point QUESTION 10 A lizard population has two alleles conferring different tolerance to heat stress. In stressful heat conditions, the following genotypes give on average the following number of offspring per reproductive season: Att/Atn 10: Att/Att=20: Atn/Atn 3. If this lizard population has an initial frequency for the allele Art of 0.3, what will the frequency of Att be in the next generation under stressful heat conditions? 0.52 0.48 0.37 0.24

Answer 1

Question 9

Answer = 0.095

Harrdy - Weinberg equilibrium equations - p2+289+92 = 1 as we can write as A²+ 2 Aa + a² = 1 or Ata = 1 where, a in the frequency of recessente altele A is the frequency of dominat allele AA is the Frequency of Homozygous dominant 2 Aa is the frequency of Heterozygous ad is the Frequency of Homozyogous recessive Now Frequency of recessive Bordition (aa) - Zoo = 0.0025 So, Frequency of recesser allele a= V0.0025 = 0.05 Frequency of dominant allele A - le = 0.95 Now, The Frequency of Heterozygotes = 2 Aa = 2X 0.95 X 0.05 = 0.095