Question

Question 8 2.5 pts Calculate heterozygosity for the following population with 4 alleles at a frequency of 0.10, 0.25, 0.45, and 0.20. O 0.69 O 0.50 O 0.48 0.25 0.31 507 I 50 OXFO AT WIP ACOLO

Answer 1

Here, 4 allele at a frequency of 0.10,0.25,0.45 and 0.20.

so p = the frequency of the dominant allele (A)
q = the frequency of the recessive allele(a)

2pq = frequency of Aa (heterozygous)

here we assum,p =0.10

q=0.25

r=0.45

s=0.20

so ,Total heterozygosity for the population will be= 2pq+2pr+2ps+2qr+2qs+2rs

=(2*0.10*0.25)+(2*0.10*0.45)+(2*0.10*0.20)+(2*0.25*0.45)+(2*0.25*0.20)+(2*0.45*0.20)

=0.05+0.09+0.04+0.225+0.1+0.18

=0.685

Ans: Heterozygosity for the following population with 4 allele is ,0.685 ~ 0.69,

so ,0.69 is the correct answer.