Here the correct option is the 4th one i.e. TCC TAG CTT AGC GGA ATC GCA TTA
Explanation -
Sanger sequencing is a method of DNA sequencing. Here, the main principle behind sequencing is that in the given DNA template solution dNTPs, DNA polymerase, DNA primer and ddNTPs(di-deoxynucleotide triphosphate) are added. Because of the dNTP, the chain growth of the primer takes lace while when the growing chain encounters the ddNTP the chain growth halts. Again, the chain growth of the next primer takes place and again it is halted by ddNTP at some other point. Thus, a larger number of fragments are obtained and then these fragments are run into the electrophoresis gel and then result are analysed.
The interpretation of the sequence of the DNA is based on the fact that the bottom of the gel is positively charged and the upside of the gel is negatively charged. Then, if we want to know the sequence of the desired DNA segment we have to note down the sequence from the positive;y charged bottom end (5' end) and stops at the negatively charged upper end (3' end).

So, the correct sequence of the given DNA segment is :
5' - TCC TAG CTT AGC GGA ATC GCA TTA - 3'
Question 8 (1 point) Above is a sequencing gel using the Sanger technique. The gel was...
Adenosine deaminases modify adenosines to form
_____________________, which is then read as
_________________________ by the translation and splicing systems,
as well as by reverse transcriptase.
Cephalopods like squid and octopus use this form of editing very
extensively in their protein-coding regions. For each of
the following, please indicate how these enzymes can alter the mRNA
to produce the indicated codon changes.
I (Ileu) is changed to V (val):
K (Lys) is changed to E (Glu):
T (Thr) is changed to A (ala):...
Please develop a Java program to read in a piece of DNA sequence from a FASTA format sequence file (alternatively you can use the getRandomSeq(long) method of the RandomSeq class to generate a piece of DNA sequence), and then print out all the codons in three forward reading frames. Design a method called codon() that can be used to find all the codons from three reading frames. The method will take in an argument, the reading frame (1, 2, or...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui ead in onder to. start and stop mak Land when to stot C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand and ONLY start on AUG and STOP when it tells you to stop Follow example below Example: DNA AGA CGG TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC UCU GCC...
8) You have extracted DNA from two different organisms. In the purification process, you find that the two test tubes have lost their identifying labels. The sequences of DNA are: Sample 1: TCC CTA TGC CCG AGG GAT ACG GGC Sample 2: CGA TCT TAA CCC GCT AGA ATT GGG The only other piece of information you have is the corresponding amino acid sequence of a particular protein for both organisms. Organism I has ala-arg-ile-gly and organism II has ala-arg-ile-pro....
8) You have extracted DNA from two different organisms. In the purification process, you find that the two test tubes have lost their identifying labels. The sequences of DNA are: Sample 1: TCC CTA TGC CCG ///// AGG GAT ACG GGC Sample 2: CGA TCT TAA CCC ///// GCT AGA ATT GGG The only other piece of information you have is the corresponding amino acid sequence of a particular protein for both organisms. Organism I has ala-arg-ile-gly and organism II...
4. Using the MK-Test, evaluate whether positive selection has driven the evolutionary divergence between Chimpanzees and Humans, Please show your work.. Second letter U C A UUU Phe UCU UAU UGU UCC Tyr UUA T UAC UAA Stop UGA UAG Stop UGG UGC Cys UCA Ser UUG FLeu UCG Trp G CUUT CUC CUA CCU CCC CCA. CCG CAU CAC His CAA CAG Gln CGU CGC Leu Pro Arg CGA CGG CUG G AUU 1 AUC lle A AUA ACU...
In regard to a colorimetric biosensor using gold nanoparticles
modified with single-stranded DNA (DNA-AuNP Hybridization Sensor),
what limit of detection and sensitivity are. In other words,
explain the limit of detection and sensitivity in complete and
clear manner. Then explain what good sensitivity and LOD would look
like in such an experiment.
Additional information:
AuNps are attached to the Thio group at the end of DNA
strands.
-S-(5')GCG CTA GAG TCG TTT CCT ATC GAC CAT GCT(3')-5- (3')CGC GAT CTC...
To Do Exit 1:00:32 41697 m 2 1:59 PN 68. -33761 5 Que at 11:5 1.5 pts 68a. Transcribe the mRNA molecule resulting from the following template DNA 33761 GTC-TAC-GCA-CTT-GGT-GCT-AGC-CTA-ACT-GAA-TCC 3761 - April Enter answer... -761 69. I 11 Second base of RNA codon +63 UUU UUC UGU _ Phenylalanine Phel VUA Serine Ser) UU LAC UAA UAG Tyrosine (Tyr) Stop Stop UUG Leul COU CAU UGC UGA Stop UGG Tryptophan (Top) CGU CGC Arginine CGA CGG Histidine CACH Proline...
Question 19 (1 point) Saved Forward Primer: GTG ATG CGG GTT TGT GCA GAC (5' to 3' on coding strand) Make a reverse primer from the following sequence, also from the coding strand, that is GC clamped and the Tm is within plus or minus 1 degree C (using the rule of thumb for calculating Tm we used in class). Please write the primer in its own 5' to 3' sequence, so we can send it out to be synthesized....
Question 19 (1 point) Forward Primer: GTG ATG CGG GTT TGT GCA GAC (5' to 3' on coding strand) Make a reverse primer from the following sequence, also from the coding strand, that is GC clamped and the Tm is within plus or minus 1 degree C (using the rule of thumb for calculating Tm we used in class). Please write the primer in its own 5' to 3' sequence, so we can send it out to be synthesized. ATC...