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Consider a cell at T = 310 K with the following ionic conditions: [K+]in = 130...

Consider a cell at T = 310 K with the following ionic conditions: [K+]in = 130 mM, [Na+]in = 14 mM, [Ca2+]in = 1.2 mM; [K+]out = 4 mM, [Na+]out = 140 mM, [Ca2+]out = 1.2x10-4 mM. Part B: if the membrane conducts only these 3 ions, and gNa=gCa=0.10gK at rest, what is the resting membrane potential?

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Answer #1

We have been given the value of conductance rather than the permeability , which is generally used in the calculation of the membrane potential .

Conductance measures the movement of charge across the membrane. Permeability measures the
capability of ions to flow across the membrane, regardless of whether they are moving across the
membrane.

This means that tha conductance is also directly propotional to the permeability.

We are given that gNa = gCa = 0.10 gK

This means the permeability will also be

pNa = pCa = 0.10 pK.

= RMP = RT en ok [kt] tona [wat o + 1 x pla [Ca 24 ) e lok[kt] praf Nat] l I la Because Ca2+ hasatcha & sR MP=RT Inax 4 + p N

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