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Lead (II) sulfate reacts with water in the following reaction: 2PbSO4(s) + 2H2O(l) -> Pb(s) + PbO2(s) + 2H2SO4(l).


3. Lead (II) sulfate reacts with water in the following reaction: Substance (kJ/mol): -285.8 277.4 PbS040 -920.0 H20 Pb (5) H
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Answer #1

\Delta H_{f},_{Pb_{s}}=0 kJ.mol^{-1}

To calculate the \Delta Hr of the given reaction,

ou 42.4. HİHMx)

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