Question

Calculate the current through the series RLC network at the resonance frequency. Vs = 10<0°, R1 = 4570, C1 = 0.279 pF, L1 = 9
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Answer #1

Solution:-

Above RLC Circuit is at resonance, in the normal situation total impedance will be:

Z= R + jwL- wc

but at resonance :

jwL = jwC

so, Z = R

now current will be:

I =\frac{V}{Z}

10 I= ---Ampere.

1 = 0.02188 Ampere

I = 21.88 mA

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