If it takes 0.200 L of 5.00 M aqueous NaOH to neutralize 0.800 L of an...

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Question

science biology

Answer 1

Answer #1

Ans) The formula used is M1 V1 = M2 V2

Let M1 = Molarity of base (NaOH) , V1 = Volume of NaOH

M2 = molarity of acid , V2 = Volume of acid . Subsituting values in formula we get,

5Mx 0.200L = 'X ' x 0.800L

1 = 0.800 'X'

'X' = 1/0.800 = 1.25 M

Thus, 0.200 L of 5.00 M aqueous NaOH neutralize 0.800L of 1.25M acid solution.

Answer 2

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