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Image for 4. (12 points) Monochromatic light of wavelength 640 mm is directed at normal incidence through a grating havi
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Answer #1

(a) d=\frac{L}{N}=\frac{10^{-2}}{6000}=1.67\times 10^{-6}m^{-1}

(b)

(b)

from the image above:

tg\vartheta =\frac{x}{l}\approx sin\vartheta

(form small angles of diffraction)

In the case of normal incidence (i=0):

dsin\vartheta =k\lambda

k=the order of diffraction

sin\vartheta =\frac{k\lambda}{d}

Using the 2 formula one obtains:

\frac{x}{l} =\frac{k\lambda}{d}

x =\frac{kl\lambda}{d}

Replace the numerical values and get the distance between the central maximum and the first order maximum.

Appendix: A zoom for the first part of this image:

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