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e. 3R/4 d. 5R/6 , BR 12 V 12. How much current is flowing in one of the 10-2 resistors? a. 2.0 A b. 1.6A c. 0.80 A d. 2.4 A e
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Answer #1

in the given circuit

20 ,10 and 10 ohms are in parallel combination

if three resistors are in parallel combination 1/R = 1/R1+R2+1/R3

resultant of these three resistors = 1/R = 1/20+1/10+1/10

R = 4 ohm

here 2 and 4 ohms are in series

total resistance R tot = 2+4 = 6 ohm

from the ohms law

v = iR

i = 12/6 = 2 A

in a series combination current is same across the resistors

so current across 2 and 4 ohms are same

voltage across 4 ohm is = 2*4 = 8 V

in a parallel combination voltage is same across the resistors

current across 10 ohm resistor is 8/10 = 0.8 A

option c

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