in the given circuit
20 ,10 and 10 ohms are in parallel combination
if three resistors are in parallel combination 1/R = 1/R1+R2+1/R3
resultant of these three resistors = 1/R = 1/20+1/10+1/10
R = 4 ohm
here 2 and 4 ohms are in series
total resistance R tot = 2+4 = 6 ohm
from the ohms law
v = iR
i = 12/6 = 2 A
in a series combination current is same across the resistors
so current across 2 and 4 ohms are same
voltage across 4 ohm is = 2*4 = 8 V
in a parallel combination voltage is same across the resistors
current across 10 ohm resistor is 8/10 = 0.8 A
option c
Three resistors of values 2 Ω,
6 Ω and 12 Ω are connected across a 2.0-V DC voltage source as
shown in Fig. 26-18. What is the total current I flowing this
circuit? 3.0 A 1.5 A 6.0 A 0.70 A 2.0 A
FIGURE 26-18 2Ω 6Ω 12Ω
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values were not given these are hw questions.
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