2.4.2 Events A, B, and C are such that A n В = A n C...

Question

Question

math Statistics-And-Probability

Answer 1

Answer #1

C)+P(AnBnC)

$P(A \cup B \cup C) = x + x + x - 0 - 0 - x/3 + 0$

Here 3P(B and C) = x, hence P(B and C) = x/3

also, P(A and B and C) = 0 as A is mutually exclusive to both B and C

$P(A \cup B \cup C) = 3x - x/3$

$P(A \cup B \cup C) = 8x/3$

Answer 2

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