Question

Consider the following system at equilibrium. S(s)+O2(g)<--->SO2(g)

1. How will adding more S(s) shift the equilibrium?

A) to the right B) to the left C) no effect

2. How will removing some SO2(g) shift the equilibrium?

A) to the right B) to the left C) no effect

3. How will decreasing the volume of the container shift the equilibrium?

A) to the right B) to the left C) no effect

Answer 1

Concepts and reason

The concept used to solve this question is to determine the equilibrium shift due to changes in the conditions.

Fundamentals

According to Le Chatelier’s principle, if equilibrium of a system is disturbed, the position of the equilibrium shifts so as to counteract that change.

For an example, if the temperature of an exothermic reaction is increased, the equilibrium shifts so that the temperature of the reaction decreases. So, the reaction moves in backward direction.

If the pressure of the system is increased, the equilibrium shifts so as to decrease the pressure. The reaction proceeds to the side with fewer moles.

The given reaction is as follows:

The expression for the equilibrium constant for the reaction is as follows:

Although is a reactant, it is not considered because it is a solid reactant.

When more is added, there is effect in the position of the equilibrium.

The given reaction is as follows:

The expression for the equilibrium constant for the reaction is as follows:

Although is a reactant, it is not considered because it is a solid reactant.

When is removed, the position of the equilibrium shifts to the right.

The given reaction is as follows:

The expression for the equilibrium constant for the reaction is as follows:

Although is a reactant, it is not considered because it is a solid reactant.

When the volume of the container is decreased, there is no effect in the position of the equilibrium.

Ans:

Therefore, there is no effect when more is added to the reaction.

Therefore, when is removed from the reaction, the position of the equilibrium shifts to the right.

Therefore, there is no effect when the volume of the container is decreased.