R3 and R4 are in series and their combination is given as
R34 = R3 + R4 = 100 + 25 = 125 ohm
R34 and R2 are in parallel and their combination is given as
R234 = R2 R34 /(R2 + R34) = 25 x 125 /(25 + 125) = 20.83 ohm
R1 R234 and R5 are in series and their combination is given as
R12345 = R1 + R234 + R5 = 25 + 20.83 + 25 = 70.83 ohm
current in R1 and R5 = 6/70.83 = 0.085 A
V1 = V5 = 0.085 x 25 = 2.125
V2 = V34 = 6 - 2.125 - 2.125 = 1.75 volts
i3 = V34/R34 = 1.75/125 = 0.014 A
Web Assign and the result in your paper submission on the Dropbox). The correct solution on...
Use figure 21.25 on Page 751 in the textbook, but the battery
voltage and resistors have been changed as following. E1 = 9 V,
E2=12V, r1=r2=1 Ohm, R1=6 Ohm, R2=2 Ohm, R3=2 Ohm. Calculate
following:
1) current, voltage, and power on resistor R1.
2) current, voltage and power on resistor R2.
3) current, voltage, and power on resistor R3.
gePhysics-OP.pdf - + + 2 Fit to page LD Page view E = 18V b d 12 12 0.5 52 RE...
Learning Goal:
To practice Problem-Solving Strategy 23.1 Resistor Circuits.
Find the currents through and the potential difference across
each resistor in the circuit shown on the diagram (Figure 1) . Use
the following values: E = 12.0V , R1 = 15.0? , R2
= 45.0? , R3 = 20.0? , and R4 = 25.0? .
PROBLEM-SOLVING STRATEGY 23.1 Resistor Circuits
We can analyze any resistor circuit by sequentially reducing
parallel and series resistor combinations to their equivalent
resistors until only...
I only need help with the discussion
there are many info that you do not need put I put just in
case as well as my data table.
please do it as soon as u can
Meauements ODeit1 Check2 Meaurements Checi3 Ced Check5 Check6 Measurements Check7 heck8 4058 33 536 1502 1035 979 119478 041 1.0319|0.554972| 64261| 153|15542033681 995781 5266566 1578807 298h 1631 119 1209430016 079096812 0.418135246 0,00032665 011890:004668155728441 0293237 1.291809502 1.22833 1.28 1952 -1116 4281 140616885511984206317 3346 8162 0.78...